(x+2)(x-7)=x^2+7x+10

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Solution for (x+2)(x-7)=x^2+7x+10 equation: 



(x+2)(x-7)=x^2+7x+10

We move all terms to the left:

(x+2)(x-7)-(x^2+7x+10)=0

We get rid of parentheses

-x^2+(x+2)(x-7)-7x-10=0

We multiply parentheses ..

-x^2+(+x^2-7x+2x-14)-7x-10=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-7x+2x-14)-7x-10=0

We get rid of parentheses

-1x^2+x^2-7x+2x-7x-14-10=0

We add all the numbers together, and all the variables

-12x-24=0

We move all terms containing x to the left, all other terms to the right

-12x=24

x=24/-12

x=-2

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